When The Test Is The Problem, Not Your Code

The greatest lie we tell ourselves during existential coding crises. That mythical moment when someone else's code—that incomprehensible mess of nested loops and questionable variable names—somehow works flawlessly on the first attempt. Meanwhile, your carefully crafted masterpiece crashes spectacularly after 17 refactors and a ritual sacrifice to the compiler gods. It's the programming equivalent of "I'm sure they'll text back" or "one more episode before bed." Pure self-delusion, but sometimes that's all that keeps us from hurling our laptops into the sun.

Content 5 Answers Active Oldest Vo You can bind the 'input' event to the textbox. This would fire every time the input changes, so when you paste something (even with right click), delete and type anything. 790 ('myTextbox").on ('input', function() do something ); If you use the change handler, this will only fire after the user deselects the input box, which may not be what you want. There is an example of both here: http:jsfiddle.net6bSX6 Share Improve this answer Follow answered Oct 9 '12 at 10:21 Timm 11.9k 4 0 30 42 197 This does not work in the Nintendo 3DS browser. The change is not detected even though the input field contains the new string. - Johan Jul 3 '13 at 11:30

The expectation vs. reality gap in programming is brutal! Non-programmers imagine us as mysterious hackers typing at lightning speed, fingers dancing across keyboards like we're hacking the Pentagon. Meanwhile, the actual programming experience is just staring blankly at the screen for hours, questioning every life decision that led to this bug. That intense "calculating the meaning of existence" face isn't deep thinking—it's us wondering if we should've become baristas instead after spending 4 hours debugging a missing semicolon.

Content Software Engineer Recruiter Your background looks perfect for this open role at our company. When can you do a 10 hour take home test and 6 rounds of interviews to see if it's a good fit?

Content In C we don't say "Missing asterisk" we say "error C2664: 'void std::vectorblock,std:allocatorTy :pushback(const block )': cannot convert argument 1 from 'std::Vectoriteratorstd::Vectorv alstd::Simpletypesblock' to 'block and i think that's beautiful

Content Judging Coworker for the error, I recently stopped making