I Just Need To Get Some Sleep

Content IT'S A CHRISTMAS TREE WITH A HEAP OF PRESENTS UNDERNEATH! ... WErE NOT INVITING YOU HOME NEXT YEAR.

The AUDACITY of developers turning catastrophic plumbing disasters into luxury water features! 💦 First panel: "OMG THERE'S A LEAK DESTROYING EVERYTHING!" Second panel: "Actually, it's our revolutionary new hydro-cooling fountain system that definitely wasn't a mistake we couldn't fix." The ultimate developer superpower isn't fixing bugs—it's rebranding them as "intentional design choices" with a straight face. I've seen codebases held together by more "features" than actual working code! The ancient art of problem-solving by problem-denying!

Ah yes, the classic tech industry pipeline: 2+ years of actual experience → underpaid → desperate → "become an expert in 3 hours" workshop. Nothing says legitimate career advancement like a LinkedIn post promising to transform you from an experienced but underpaid SQL developer into an "AI in SQL" expert faster than it takes to restore a corrupted database. For reference, 8 LPA (Lakhs Per Annum) is roughly $10K USD, so this guru is essentially targeting professionals who know they're worth more but haven't figured out how to escape the salary trap. The irony is that anyone with actual SQL experience would immediately recognize this query returns nothing but empty promises.

C++ developers watching Rust evangelists talk about memory safety is the programming equivalent of a wolf staring down a chihuahua. Sure, the chihuahua is making valid points about not eating the neighbors, but the wolf's been managing just fine with raw power and sharp teeth for decades, thank you very much. After 35 years of manual memory management, we've seen some things. And yeah, maybe we've caused a few segfaults that took down production servers at 2AM, but that's just character building.

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Content bool isEven(int x) switch(x) Case return true; case 1: return false; break bool isEven(int x) while (x 1) - 2 if (x: 0) return true; else return false; bool isEven(int x) if (x 2 0) return true; else return false; bool isEven (int x) return x 1;