Content
dimension: age type: string sql: case when S(dateofbirth) LIKE '81939' then '80 when S(dateofbirth) LIKE 1940 then '79 when S(dateofbirth LIKE 81941' then '78 when (dateofbirth) LIKE 1942 then '77 when Sdateofbirth) LIKE '1943 then '76 when Sdateofbirth) LIKE 1944' then '75 "89' ite Bleate.of Strth) LINE 19428 78 Gen she Sidate,of bicth) LIKE "1943t then 76' da sidate, of birth LIke then 175