Sometimes I'm not updated on changes to the plan

The function loops through ALL USERS to find one with matching credentials instead of using a proper query. The comment is the chef's kiss: "This only works because there are not many users." It's like saying "my car doesn't need brakes because I don't drive fast." Bonus security nightmare: they're storing password hashes but comparing them directly instead of hashing the input password first. This authentication is basically a time bomb wrapped in spaghetti code!

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When your code editor starts psychoanalyzing you instead of just fixing the missing semicolon. That empty function isn't just syntactically incorrect—it's having a full-blown philosophical breakdown. Somewhere, Nietzsche is nodding approvingly at VS Code while whispering, "The abyss of empty functions also gazes into you."

Content : Anonymous 080922(Tue)13:38:56 No.88068483 low-level programming C game development C high performance code 58 KB PNG C scientific programming Python with libraries written in C machine learning Python with libraries written in C front-end web development Javascript back-end web development Javascript You only need three languages for everything: C, Python and Javascript. You don't need more. : Anonymous 080922(Tue)13:40:47 No.88068493 88068786 88069150 88069189 88076569 88085798 : Anonymous 080922(Tue)13:42:19 No.88068506 Anonymous 080922(Tue)13:44:44 No.88068520 I thought C was being replaced by (new language)

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Content Sg ChatGPT No, there is no built-in JavaScript function to fill a string with a character from the left until a certain length. However, you can create your own function which may look something like this: Insert New function leftpad(str, len, char) if (str. length len) return str; var missing len - str. length; for (var i 0; 1 missing; i) str char str; return str; g You padstart? g ChatGPT Yes, the method you are looking for is String.prototype.padStart ( ). It takes in two arguments: Target length - Number of characters in the resulting string. Character to pad with (optional).